题目内容
在公式
=
+
中,已知正数R、R1(R≠R1),那么R2=
.
| 1 |
| R |
| 1 |
| R1 |
| 1 |
| R2 |
| RR1 |
| R1-R |
| RR1 |
| R1-R |
分析:首先求得
,然后两边求倒数即可.
| 1 |
| R2 |
解答:解:
=
-
=
,
则R2=
,
故答案是:
.
| 1 |
| R2 |
| 1 |
| R |
| 1 |
| R1 |
| R1-R |
| RR1 |
则R2=
| RR1 |
| R1-R |
故答案是:
| RR1 |
| R1-R |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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在公式
=
+
中,(r1+r2≠0),用r1、r2表示R是( )
| 1 |
| R |
| 1 |
| r1 |
| 1 |
| r2 |
| A、R=r1+r2 | ||||
| B、R=r1r2 | ||||
C、
| ||||
D、R=
|