题目内容
(1)(| 12 |
| m2-9 |
| 2 |
| 3+m |
| 1 |
| m-3 |
(2)2-2+(
| 1 |
| 2 |
分析:(1)本题须先对括号里边的式子进行变形,再利用乘法的分配律分别相乘即可求出结果.
(2)本题须先分别求出每一项的值,再把所得结果合并即可.
(2)本题须先分别求出每一项的值,再把所得结果合并即可.
解答:解:(1)(
+
)÷
,
=[
+
]•(m-3),
=
•(m-3)+
•(m-3),
=2;
(2)2-2+(
)-3-2-3×2-(3.14-π)0,
=
+8-
×2-1,
=8-1,
=7.
| 12 |
| m2-9 |
| 2 |
| 3+m |
| 1 |
| m-3 |
=[
| 12 |
| (m+3)(m-3) |
| 2 |
| 3+m |
=
| 12 |
| (m+3)(m-3) |
| 2 |
| 3+m |
=2;
(2)2-2+(
| 1 |
| 2 |
=
| 1 |
| 4 |
| 1 |
| 8 |
=8-1,
=7.
点评:本题主要考查了分式的混合运算,解题时要注意简便方法的综合应用.
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