题目内容
先化简,再求(
-
)÷
的值,其中x=-
.
| x |
| x-2 |
| x |
| x+2 |
| 4x |
| 2-x |
| 1 |
| 2 |
分析:先将括号内的部分通分,相减后再把除法转化为乘法,然后约分即可.
解答:解:原式=[
]•
=
•
=
•
=-
,
当x=-
时,原式=-
=-
=-
.
| x(x+2)-x(x-2) |
| (x-2)(x+2) |
| 2-x |
| 4x |
=
| x2+2x-x2+2x |
| (x-2)(x+2) |
| 2-x |
| 4x |
=
| 4x |
| (x-2)(x+2) |
| 2-x |
| 4x |
=-
| 1 |
| x+2 |
当x=-
| 1 |
| 2 |
| 1 | ||
-
|
| 1 | ||
|
| 2 |
| 3 |
点评:本题考查了分式的化简求值,化简后将数值代入即可.
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