题目内容
10.若关于x,y的二元一次方程组$\left\{\begin{array}{l}{2x+y=3k-1}\\{x+2y=-2}\end{array}\right.$的解满足x-y>4,求k的取值范围.分析 用①-②可得出x-y的表达式,再由x-y>4求出m的取值范围即可.
解答 解:$\left\{\begin{array}{l}2x+y=3k-1①\\ x+2y=-2②\end{array}\right.$,①-②得,x-y=3k+1,
∵x-y>4,
∴3k+1>4,解得k>1.
点评 本题考查的是解一元一次不等式,根据题意得出x-y的表达式是解答此题的关键.
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