题目内容
求| x2-1 |
| x2+2x+1 |
| 2 |
分析:先把分式化简,一定要化到最简,然后把x的值代入即可.
解答:解:
=
=
,
当x=
-1时,
原式=
=
=
=1-
.
| x2-1 |
| x2+2x+1 |
| (x+1)(x-1) |
| (x+1)2 |
=
| x-1 |
| x+1 |
当x=
| 2 |
原式=
| x-1 |
| x+1 |
| ||
|
=
| ||
|
=1-
| 2 |
点评:本题考查了分式的化简代值问题,注意一定要化到最简.
练习册系列答案
相关题目