题目内容
整式加减
①-ab+2ba-5ab
②5-m-(-5m+
)
③(x2-3x+1)+(
x2-5x-3)
④-7x2+5x-2(x2-3x)
⑤3y-2(y-1)+3(4-y)
⑥-3[y-(3x2-3xy)]-[y+2(4x2-4xy)].
①-ab+2ba-5ab
②5-m-(-5m+
| 1 |
| 2 |
③(x2-3x+1)+(
| 3 |
| 2 |
④-7x2+5x-2(x2-3x)
⑤3y-2(y-1)+3(4-y)
⑥-3[y-(3x2-3xy)]-[y+2(4x2-4xy)].
考点:整式的加减
专题:
分析:①合并同类项即可;
①先去括号,再合并同类项即可;
③先去括号,再合并同类项即可;
④先算乘法,再合并即可;
⑤先去括号,再合并同类项即可;
⑥先去小括号,再去中括号,最后合并即可.
①先去括号,再合并同类项即可;
③先去括号,再合并同类项即可;
④先算乘法,再合并即可;
⑤先去括号,再合并同类项即可;
⑥先去小括号,再去中括号,最后合并即可.
解答:解:①原式=(-1+2-5)ab=-4ab;
②原式=5-m+5m-
=4m+4
;
③原式=x2-3x+1+
x2-5x-3
=
x2-8x-2;
④原式=-7x2+5x-2x2+6x
=-9x2+11x;
⑤原式=3y-2y+2+12-3y
=-2y+14;
⑥原式=-3[y-3x2+3xy]-[y+8x2-8xy]
=-3y+9x2-9xy-y-8x2+8xy
=-4y+x2-xy.
②原式=5-m+5m-
| 1 |
| 2 |
=4m+4
| 1 |
| 2 |
③原式=x2-3x+1+
| 3 |
| 2 |
=
| 5 |
| 2 |
④原式=-7x2+5x-2x2+6x
=-9x2+11x;
⑤原式=3y-2y+2+12-3y
=-2y+14;
⑥原式=-3[y-3x2+3xy]-[y+8x2-8xy]
=-3y+9x2-9xy-y-8x2+8xy
=-4y+x2-xy.
点评:本题考查了整式的混合运算的应用,主要考查学生的计算能力,题目比较好,难度适中.
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