题目内容
| AE |
| EB |
| 2 |
| 3 |
A、
| ||||
B、
| ||||
C、
| ||||
D、
|
分析:由AD∥EF∥BC,且
=
,根据平行线分线段成比例定理,即可求得
=
=
,继而求得答案.
| AE |
| EB |
| 2 |
| 3 |
| AE |
| EB |
| DF |
| FC |
| 2 |
| 3 |
解答:解:∵AD∥EF∥BC,且
=
,
∴
=
=
,
∴
=
.
故选D.
| AE |
| EB |
| 2 |
| 3 |
∴
| AE |
| EB |
| DF |
| FC |
| 2 |
| 3 |
∴
| DF |
| DC |
| 2 |
| 5 |
故选D.
点评:此题考查了平行线分线段成比例定理.此题比较简单,注意解此题的关键是数形结合思想的应用.
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