题目内容

x1,x2,x3,x4,x5,x6都是正数,且
x2x3x4x5x6
x1
=1
x1x3x4x5x6
x2
=2
x1x2x4x5x6
x3
=3
x1x2x3x5x6
x4
=4
x1x2x3x4x6
x5
=6
x1x2x3x4x5
x6
=9
,则x1x2x3x4x5x6=
 
考点:整式的混合运算
专题:整体思想
分析:六个等式左右两边相乘,开四次方即可求出所求式子的值.
解答:解:∵
x2x3x4x5x6
x1
=1,
x1x3x4x5x6
x2
=2,
x1x2x4x5x6
x3
=3,
x1x2x3x5x6
x4
=4,
x1x2x3x4x6
x5
=6,
x1x2x3x4x5
x6
=9,
x2x3x4x5x6
x1
x1x3x4x5x6
x2
x1x2x4x5x6
x3
x1x2x3x5x6
x4
x1x2x3x4x6
x5
x1x2x3x4x5
x6
=1×2×3×4×6×9,
整理得:(x1x2x3x4x5x64=2×2×2×2×3×3×3×3=(2×3)4=64
则x1x2x3x4x5x6=6.
故答案为:6.
点评:此题考查了整式的混合运算,熟练掌握运算法则是解本题的关键.
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