题目内容
计算
(1)(-2)-(-3)+20-(+3)-(+20)+(-8)
(2)-27÷
×(-
)+4-4×(-
)
(3)[(-1)2014+(1-
)×
]÷(-32+2)
(1)(-2)-(-3)+20-(+3)-(+20)+(-8)
(2)-27÷
| 9 |
| 4 |
| 4 |
| 9 |
| 1 |
| 3 |
(3)[(-1)2014+(1-
| 1 |
| 2 |
| 1 |
| 3 |
考点:有理数的混合运算
专题:
分析:(1)先化简,再分类计算;
(2)先算乘除,再算加减;
(3)先算乘方和减法,再算乘法,再算括号里面的加减,最后算除法.
(2)先算乘除,再算加减;
(3)先算乘方和减法,再算乘法,再算括号里面的加减,最后算除法.
解答:解:(1)原式=-2+3+20-3-20-8
=-33+23
=-10;
(2)原式=27×
×
+4+
=
+4+
=
;
(3)原式=[1+
×
]÷(-9+2)
=[1+
]÷(-7)
=
×(-
)
=-
.
=-33+23
=-10;
(2)原式=27×
| 4 |
| 9 |
| 4 |
| 9 |
| 4 |
| 3 |
=
| 16 |
| 3 |
| 4 |
| 3 |
=
| 32 |
| 3 |
(3)原式=[1+
| 1 |
| 2 |
| 1 |
| 3 |
=[1+
| 1 |
| 6 |
=
| 7 |
| 6 |
| 1 |
| 7 |
=-
| 1 |
| 6 |
点评:此题考查有理数的混合运算,掌握运算顺序,正确判定运算符号是解决问题的关键.
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