题目内容
(2011•资阳)化简:(1-
)÷
.
| 1 |
| x+4 |
| x2-9 |
| x+4 |
分析:先把括号里面的进行通分,再把x2-9进行因式分解,然后把除法转化成乘法,再进行约分即可求出答案.
解答:解:(1-
)÷
=
÷
=
÷
=
×
=
.
| 1 |
| x+4 |
| x2-9 |
| x+4 |
=
| (x+4)-1 |
| x+4 |
| x2-9 |
| x+4 |
=
| (x+4)-1 |
| x+4 |
| (x+3)(x-3) |
| x+4 |
=
| x+3 |
| x+4 |
| x+4 |
| (x+3)(x-3) |
=
| 1 |
| x-3 |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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