题目内容
当x=cot60°时,代数式
÷(x+
)的值是( )
| x2-3x |
| x-2 |
| 3 |
| 2-x |
A、
| ||||
B、
| ||||
C、
| ||||
D、
|
分析:此式是带有括号的分式的混合运算,应先化简再求值.
解答:解:原式=
÷
=
=
=
.
当x=
时,原式=
=
.
故选A.
| x(x-3) |
| x-2 |
| x(x-2)-3 |
| x-2 |
=
| x(x-3) |
| x2-2x-3 |
=
| x(x-3) |
| (x-3)(x+1) |
=
| x |
| x+1 |
当x=
| ||
| 3 |
| ||||
|
| ||
| 2 |
故选A.
点评:此题要注意括号里的运算,通分时的最简公分母是x-2,要注意把分母2-x变为-(x-2).
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