题目内容
2006加上它的| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2006 |
分析:第一个数为2006(1+
),第二个数为2006(1+
)(1+
),第三个数为2006(1+
)(1+
)(1+
),…依此类推,最后一个数为2006(1+
)(1+
)(1+
)…(1+
),化简得出结果即可.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2006 |
解答:解:2006(1+
)(1+
)(1+
)…(1+
),
=2006×
×
×
×…×
,
=1003×2007,
=2013021.
故答案为:2013021.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2006 |
=2006×
| 3 |
| 2 |
| 4 |
| 3 |
| 5 |
| 4 |
| 2007 |
| 2006 |
=1003×2007,
=2013021.
故答案为:2013021.
点评:本题考查了数字的变化规律,最后一个数用公式2006(1+
)(1+
)(1+
)…(1+
)表示出来是解题的关键.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2006 |
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