题目内容

2b+2c
a
=
2a+2c
b
=
2a+2b
c
=k,则k的值为(  )
A.4B.0C.-2或0D.4或-2
2b+2c
a
=
2a+2c
b
=
2a+2b
c
=k,
b+c
a
=
a+c
b
=
a+b
c
=
1
2
k,
分情况进行:当a+b+c≠0时,根据等比性质,得
1
2
k=
2c+2a+2b
c+a+b
=2,则k=4;
当a+b+c=0时,则a+b=-c,
1
2
k=-1,则k=-2.
故选D.
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