题目内容
化简与计算:
(1)
•
÷
;
(2)
-
.
(1)
| 3a |
| b |
| ab2 |
| -a3b2 |
| 6b |
| a2 |
(2)
| 2 |
| x2-4 |
| 1 |
| 2x-4 |
分析:(1)先把除法运算转化成乘法运算,进行约分化简即可;
(2)先通分,再进行分式的减法计算即可.
(2)先通分,再进行分式的减法计算即可.
解答:解:(1)
•
÷
=-
•
•
=-
;
(2)
-
=
-
=
=-
.
| 3a |
| b |
| ab2 |
| -a3b2 |
| 6b |
| a2 |
=-
| 3a |
| b |
| ab2 |
| a3b2 |
| a2 |
| 6b |
=-
| a |
| 2b |
(2)
| 2 |
| x2-4 |
| 1 |
| 2x-4 |
=
| 4 |
| 2(x+2)(x-2) |
| x+2 |
| 2(x+2)(x-2) |
=
| 2-x |
| 2(x+2)(x-2) |
=-
| 1 |
| 2x+4 |
点评:本题主要考查分式的混合运算,通分、因式分解和约分是解答的关键.
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