ÌâÄ¿ÄÚÈÝ

ºìÐÇʳƷ³§¶À¼ÒÉú²ú¾ßÓеط½ÌØÉ«µÄijÖÖʳƷ£¬²úÁ¿y1(Íòǧ¿Ë)ÓëÏúÊÛ¼Û¸ñx(Ôª£¯Ç§¿Ë)(2¡Üx¡Ü10)Âú×㺯Êý¹ØÏµÊ½y1=0.5x+11£®¾­Êг¡µ÷²é·¢ÏÖ£º¸ÃʳƷÊг¡ÐèÇóÁ¿y2(Íòǧ¿Ë)ÓëÏúÊÛ¼Û¸ñx(Ôª£¯Ç§¿Ë)(2¡Üx¡Ü10)µÄ¹ØÏµÈçͼËùʾ£®µ±²úÁ¿Ð¡ÓÚ»òµÈÓÚÊг¡ÐèÇóÁ¿Ê±£¬Ê³Æ·½«±»È«²¿ÊÛ³ö£»µ±²úÁ¿´óÓÚÊг¡ÐèÇóÁ¿Ê±£¬Ö»ÄÜÊÛ³ö·ûºÏÊг¡ÐèÇóÁ¿µÄʳƷ£¬Ê£ÓàʳƷÓÉÓÚ±£ÖÊÆÚ¶Ì½«±»ÎÞÌõ¼þÏú»Ù£®

(1)Çóy2ÓëxµÄº¯Êý¹ØÏµÊ½£»

(2)µ±ÏúÊÛ¼Û¸ñΪ¶àÉÙʱ£¬²úÁ¿µÈÓÚÊг¡ÐèÇóÁ¿?

(3)Èô¸ÃʳƷÿǧ¿ËµÄÉú²ú³É±¾ÊÇ2Ôª£¬ÊÔÇó³§¼ÒËùµÃÀûÈóW(ÍòÔª)ÓëÏúÊÛ¼Û¸ñx(Ôª£¯Ç§¿Ë) (2¡Üx¡Ü10)Ö®¼äµÄº¯Êý¹ØÏµÊ½£®

 

¡¾´ð°¸¡¿

ÂÔ

¡¾½âÎö¡¿½â£º£¨1£©É躯ÊýµÄ½âÎöʽΪy2=kx+b£¬°Ñ£¨2£¬12£©ºÍ£¨10£¬4£©´úÈ뺯ÊýµÄ½âÎöʽ¿ÉµÃ£º£¬½âµÃ£¬ËùÒÔº¯ÊýµÄ½âÎöʽΪy2=£­x+14.

£¨2£©ÓÉÌâÒâ¿ÉµÃ£º0.5x+11=£­x+14£¬ËùÒÔx=2£¬ËùÒÔµ±ÏúÊÛ¼Û¸ñΪ2Ԫʱ£¬²úÁ¿µÈÓÚÊг¡ÐèÇóÁ¿.

£¨3£©Éèµ±ÏúÊÛµ¥¼ÛΪxʱ£¬²úÁ¿Îªy£¬

ÔòÓÉÌâÒâµÃ£ºW=(x£­2)y=(x£­2)(0.5x+11)

=0.5x2+10x£­22

=(2¡Üx¡Ü10)

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø