题目内容
计算:[(3x﹣2y)2(3x+2y)2﹣(9x2+4y2)2]÷(﹣16xy)2.
解:原式=[(9x2﹣4y2)2﹣(9x2+4y2)2]÷(﹣16xy)2.
=(81x4﹣72x2y2+16y4﹣81x4﹣72x2y2﹣16y4)÷(﹣16xy)2.
=﹣144x2y2÷256x2y2
=﹣
.
=(81x4﹣72x2y2+16y4﹣81x4﹣72x2y2﹣16y4)÷(﹣16xy)2.
=﹣144x2y2÷256x2y2
=﹣
练习册系列答案
相关题目