题目内容
已知:x+
=3; x+
=5; x+
=7,根据以上规律,求x+
=2n+4的解.
| 2 |
| x |
| 6 |
| x |
| 12 |
| x |
| n2+n |
| x-3 |
考点:分式方程的解
专题:
分析:根据计算、观察,可得规律:x+
=2n+1,的解为=n或x=n+1,根据规律,可得答案.
| n2+n |
| x |
解答:解:x+
=3可转化为x2-3x+2=0,解得x1=1,x2=2,
x+
=5可转化为x2-5x+6=0解得x1=2,x2=3,
x+
=2n+1,的解为=n或x=n+1,
x+
=2n+4可转化为x-3+
=2n+1,得x-3=n或x-3=n+1,
x1=n+3,x2=n+4.
| 2 |
| x |
x+
| 6 |
| x |
x+
| n2+n |
| x |
x+
| n2+n |
| x-3 |
| n2+n |
| x-3 |
x1=n+3,x2=n+4.
点评:本题考查了分式方程的解,发现规律是解题关键.
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