题目内容
化简求值:| x2+1 |
| x+1 |
| 2 |
| x+1 |
分析:本题可先把分式化简,然后将x的值代入化简后的式子求值即可.
解答:解:
-
=
=
=
=x-1,
当x=2时,原式=1.
| x2+1 |
| x+1 |
| 2 |
| x+1 |
| x2+1-2 |
| x+1 |
| x2-1 |
| x+1 |
| (x+1)(x-1) |
| x+1 |
当x=2时,原式=1.
点评:本题主要考查分式的化简求值,把分式化到最简是解题的关键.
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