题目内容
化简:| x2-y2 |
| x+y |
| 4x(x-y)+y2 |
| 2x-y |
分析:首先把各分式进行约分,然后进行加减运算.
解答:解:原式=
-
=x-y-
=x-y-2x+y
=-x.
| (x+y)(x-y) |
| x+y |
| 4x2-4xy+y2 |
| 2x-y |
=x-y-
| (2x-y)2 |
| 2x-y |
=x-y-2x+y
=-x.
点评:本题不必要把两式子先通分,约分后就能加减运算了.
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