题目内容
8.若$\left\{\begin{array}{l}{x=-3}\\{y=2}\end{array}\right.$是关于x,y的方程组$\left\{\begin{array}{l}{4x+y=a}\\{bx-2y=2}\end{array}\right.$的解,则a+b的值为( )| A. | 8 | B. | -8 | C. | 12 | D. | -12 |
分析 把$\left\{\begin{array}{l}{x=-3}\\{y=2}\end{array}\right.$代入方程组$\left\{\begin{array}{l}{4x+y=a}\\{bx-2y=2}\end{array}\right.$后来求a+b的值即可.
解答 解:依题意得:$\left\{\begin{array}{l}{-3×4+2=a}\\{-3b-2×2=2}\end{array}\right.$,
解得$\left\{\begin{array}{l}{a=-10}\\{b=-2}\end{array}\right.$,
所以a+b=-10-2=-12.
故选:D.
点评 本题考查了二元一次方程组的解的定义.此题利用代入法求得a、b的值.
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