题目内容
(2013•鞍山)先化简,再求值:
÷(x-
)-1,其中x=
+1.
| x+1 |
| x |
| 1+x2 |
| 2x |
| 2 |
分析:将括号内的部分通分后相减,再将除法转化为后解答.
解答:解:原式=
÷(
-
)-1
=
÷
-1
=
•
-1
=
-1.
当x=
+1时,原式=
-1,
=
-1
=
-1.
| x+1 |
| x |
| 2x2 |
| 2x |
| 1+x2 |
| 2x |
=
| x+1 |
| x |
| x2-1 |
| 2x |
=
| x+1 |
| x |
| 2x |
| (x-1)(x+1) |
=
| 2 |
| x-1 |
当x=
| 2 |
| 2 | ||
|
=
| 2 | ||
|
=
| 2 |
点评:本题考查了分式的化简求值,能正确进行因式分解是解题的关键.
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