题目内容
化简:| x2+x |
| x-1 |
| x2-1 |
| x2-2x+1 |
分析:此题要先把除法转化为乘法来做,通过因式分解、约分后,再算减法.
解答:解:原式=
•
-(2x-1)
=x-2x+1
=-x+1.
| x(x+1) |
| x-1 |
| (x-1)2 |
| (x+1)(x-1) |
=x-2x+1
=-x+1.
点评:此题运算顺序:先除后减,用到了分解因式、约分、合并同类项等知识点.
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题目内容
化简:| x2+x |
| x-1 |
| x2-1 |
| x2-2x+1 |
| x(x+1) |
| x-1 |
| (x-1)2 |
| (x+1)(x-1) |