题目内容
先化简| 1 |
| x+1 |
| 1 |
| x2-1 |
| x+1 |
| x2-2x+1 |
| 3 |
分析:这道求代数式值的题目,不应考虑把x的值直接代入,通常做法是先把代数式化简,然后再代入求值.注意x不能取1或-1.
解答:解:原式=
-
×
=
-
=
-
=
,
取x=
-1,
原式=
=
| 1 |
| x+1 |
| 1 |
| (x+1)(x-1) |
| (x-1)2 |
| x+1 |
=
| 1 |
| x+1 |
| x-1 |
| (x+1)2 |
=
| x+1 |
| (x+1)2 |
| x-1 |
| (x+1)2 |
=
| 2 |
| (x+1)2 |
取x=
| 3 |
原式=
| 2 | ||
(
|
=
| 2 |
| 3 |
点评:注意化简后,代入的数不能使原分式的分母的值为0.
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