题目内容
先化简(| 3x |
| x-1 |
| x |
| x+1 |
| x2-1 |
| x |
| 2 |
分析:首先把括号里式子先通分,然后进行乘法运算,进行约分化简,最后代值计算.
解答:解:原式=
×
=
×
=2x+4;
当x=
-2时,原式=2
.
| 3x(x+1)-x(x-1) |
| (x-1)(x+1) |
| (x+1)(x-1) |
| x |
=
| 2x(x+2) |
| (x-1)(x+1) |
| (x+1)(x-1) |
| x |
=2x+4;
当x=
| 2 |
| 2 |
点评:本题的关键是化简,然后把给定的值代入求值.
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