题目内容
(1)化简:(
-
)•
;
(2)
•
+(3x+1).
| 1 |
| x+1 |
| 1 |
| x-1 |
| x2-1 |
| 2 |
(2)
| x2-1 |
| x |
| x |
| x+1 |
分析:(1)先把括号里面的式子进行通分,再合并,然后进行约分,即可得出答案;
(2)先将第一个分式的分子分解因式,根据分式的乘法运算再进行约分,然后合并同类项,即可得出答案.
(2)先将第一个分式的分子分解因式,根据分式的乘法运算再进行约分,然后合并同类项,即可得出答案.
解答:解:(1)(
-
)•
=(
-
)•
=
)•
=-1;
(2)
•
+(3x+1)
=
•
+(3x+1)
=(x-1)+3x+1
=x-1+3x+1
=4x.
| 1 |
| x+1 |
| 1 |
| x-1 |
| x2-1 |
| 2 |
=(
| x-1 |
| (x+1)(x-1) |
| x+1 |
| (x+1)(x-1) |
| (x+1)(x-1) |
| 2 |
=
| -2 |
| (x+1)(x-1) |
| (x+1)(x-1) |
| 2 |
=-1;
(2)
| x2-1 |
| x |
| x |
| x+1 |
=
| (x+1)(x-1) |
| x |
| x |
| x+1 |
=(x-1)+3x+1
=x-1+3x+1
=4x.
点评:此题考查了分式的混合运算,关键是通分,合并同类项,注意混合运算的运算顺序,把分式化到最简.
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