题目内容
计算,并把结果表示成循环小数:(34.8| • |
| 3 |
| • |
| 4 |
| • |
| 7 |
| • |
| 8 |
分析:首先把3.
和34.8
化成分数,然后求和再除以41,最后再把分数表示成循环小数.
| • |
| 7 |
| • |
| 8 |
| • |
| 3 |
| • |
| 4 |
解答:解:3.
=3
,34.8
=34
,
故知:(34.8
+3.
)=(3
+34
),
即(34.8
+3.
)÷41=(3
+34
)÷41=
=0.9
,
故答案为0.9
.
| • |
| 7 |
| • |
| 8 |
| 78 |
| 99 |
| • |
| 3 |
| • |
| 4 |
| 826 |
| 990 |
故知:(34.8
| • |
| 3 |
| • |
| 4 |
| • |
| 7 |
| • |
| 8 |
| 78 |
| 99 |
| 826 |
| 990 |
即(34.8
| • |
| 3 |
| • |
| 4 |
| • |
| 7 |
| • |
| 8 |
| 78 |
| 99 |
| 826 |
| 990 |
| 38236 |
| 990×41 |
| • |
| 4 |
| • |
| 2 |
故答案为0.9
| • |
| 4 |
| • |
| 2 |
点评:本题主要考查有理数无理数的概念与运算的知识点,解答本题的关键是会把循环小数化成分数,此题难度较大.
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