题目内容
计算:
①0.25-
+(-1
)-(+3
)
②-105
÷(-
)
③-32+(-2
)2×(-
)+|-22|
④(-1)2013-{(-3)3-[3+
×(-1
)]÷(-2)}.
①0.25-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
②-105
| 5 |
| 9 |
| 5 |
| 3 |
③-32+(-2
| 1 |
| 2 |
| 4 |
| 25 |
④(-1)2013-{(-3)3-[3+
| 2 |
| 3 |
| 1 |
| 2 |
考点:有理数的混合运算
专题:
分析:①先算同分母分数,再相加即可求解;
②将除法变为乘法,根据乘法分配律计算;
③④按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的.
②将除法变为乘法,根据乘法分配律计算;
③④按照有理数混合运算的顺序,先乘方后乘除最后算加减,有括号的先算括号里面的.
解答:解:①0.25-
+(-1
)-(+3
)
=
-(
+3
)-1
=
-4-1
=
-5
=-5
;
②-105
÷(-
)
=(105+
)×
=105×
+
×
=63+
=63
;
③-32+(-2
)2×(-
)+|-22|
=-9+
×(-
)+4
=-9-1+4
=-6;
④(-1)2013-{(-3)3-[3+
×(-1
)]÷(-2)}
=-1-{-27-[3-1]÷(-2)}
=-1-{-27-2÷(-2)}
=-1-{-27+1}
=-1+26
=25.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
=
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
=
| 1 |
| 4 |
| 1 |
| 3 |
=
| 1 |
| 4 |
| 1 |
| 3 |
=-5
| 1 |
| 12 |
②-105
| 5 |
| 9 |
| 5 |
| 3 |
=(105+
| 5 |
| 9 |
| 3 |
| 5 |
=105×
| 3 |
| 5 |
| 5 |
| 9 |
| 3 |
| 5 |
=63+
| 1 |
| 3 |
=63
| 1 |
| 3 |
③-32+(-2
| 1 |
| 2 |
| 4 |
| 25 |
=-9+
| 25 |
| 4 |
| 4 |
| 25 |
=-9-1+4
=-6;
④(-1)2013-{(-3)3-[3+
| 2 |
| 3 |
| 1 |
| 2 |
=-1-{-27-[3-1]÷(-2)}
=-1-{-27-2÷(-2)}
=-1-{-27+1}
=-1+26
=25.
点评:本题考查的是有理数的运算能力.注意:
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
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