题目内容
(2013•吴中区二模)先化简,再求值:
•
-
,其中x=
,y=-1.
| x+y |
| x3-x2y |
| x2-2xy+y2 |
| x+y |
| 2 |
| x |
| 2 |
分析:首先正确将分式的分子与分母进行因式分解,进而进行分式的通分、约分,并准确代值计算.
解答:解:原式=
•
-
,
=
-
,
=
-
,
=-
,
当x=
,y=-1时,原式=-
=
.
| x+y |
| x2(x-y) |
| (x-y)2 |
| x+y |
| 2 |
| x |
=
| x-y |
| x2 |
| 2 |
| x |
=
| x-y |
| x2 |
| 2x |
| x2 |
=-
| x+y |
| x2 |
当x=
| 2 |
| ||
| 2 |
1-
| ||
| 2 |
点评:本题考查了分式的化简求值,解题的关键是正确化简所给分式.
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