题目内容
先化简,再求值:
÷(m+2-
),其中m是方程x2+3x-2=0的根.
| m-3 |
| 3m2-6m |
| 5 |
| m-2 |
考点:分式的化简求值,一元二次方程的解
专题:
分析:首先将括号里面通分,进而将分子分母因式分解,进而求出即可.
解答:解:
÷(m+2-
)
=
÷[
-
]
=
×
=
=
,
∵m是方程x2+3x-2=0,
∴m2+3m-2=0,
∴m2+3m=2,
∴原式=
=
.
| m-3 |
| 3m2-6m |
| 5 |
| m-2 |
=
| m-3 |
| 3m(m-2) |
| (m+2)(m-2) |
| m-2 |
| 5 |
| m-2 |
=
| m-3 |
| 3m(m-2) |
| m-2 |
| (m-3)(m+3) |
=
| 1 |
| 3m(m+3) |
=
| 1 |
| 3(m2+3m) |
∵m是方程x2+3x-2=0,
∴m2+3m-2=0,
∴m2+3m=2,
∴原式=
| 1 |
| 3×2 |
| 1 |
| 6 |
点评:此题主要考查了分式的化简求值以及一元二次方程的解,正确化简分式是解题关键.
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