题目内容
19.下列方程组①$\left\{\begin{array}{l}{2x-y=1}\\{y=3z+1}\end{array}\right.$ ②$\left\{\begin{array}{l}{x=2}\\{3y-x=1}\end{array}\right.$③$\left\{\begin{array}{l}{xy=1}\\{x+2y=3}\end{array}\right.$④$\left\{\begin{array}{l}{\frac{1}{x}+\frac{1}{y}=1}\\{x+y=1}\end{array}\right.$⑤$\left\{\begin{array}{l}{x=1}\\{y=1}\end{array}\right.$,其中是二元一次方程组的有( )| A. | 2个 | B. | 3个 | C. | 4个 | D. | 5个 |
分析 组成二元一次方程组的两个方程应共含有两个未知数,且未知数的项最高次数都应是一次的整式方程.
解答 解:①$\left\{\begin{array}{l}{2x-y=1}\\{y=3z+1}\end{array}\right.$ 是三元一次方程组;
②$\left\{\begin{array}{l}{x=2}\\{3y-x=1}\end{array}\right.$是二元一次方程组;
③$\left\{\begin{array}{l}{xy=1}\\{x+2y=3}\end{array}\right.$是二元二次方程组;
④$\left\{\begin{array}{l}{\frac{1}{x}+\frac{1}{y}=1}\\{x+y=1}\end{array}\right.$是分式方程;
⑤$\left\{\begin{array}{l}{x=1}\\{y=1}\end{array}\right.$是二元一次方程组,
故选:A.
点评 本题考查了二元一次方程组的解,一定要紧扣二元一次方程组的定义“由两个二元一次方程组成的方程组”,细心观察排除,得出正确答案.
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