题目内容
①(| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
②-22+3×(-1)4-(-4)×5
③3a2+5-2a2-2a+3a-8
④3(-ab+2a)-2(3a-b)
分析:运用有理数的运算法则,以及乘方运算,去括号,进行合并同类项,可以得出结果.
解答:解:①(
+
-
)×(-24),
=
×(-24)+
×(-24)-
×(-24),
=-9-4+18,
=5;
②-22+3×(-1)4-(-4)×5,
=-4+3+20,
=19;
③3a2+5-2a2-2a+3a-8,
=a2+a-3;
④3(-ab+2a)-2(3a-b),
=-3ab+6ab-6a+2b,
=3ab-6a+2b.
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=
| 3 |
| 8 |
| 1 |
| 6 |
| 3 |
| 4 |
=-9-4+18,
=5;
②-22+3×(-1)4-(-4)×5,
=-4+3+20,
=19;
③3a2+5-2a2-2a+3a-8,
=a2+a-3;
④3(-ab+2a)-2(3a-b),
=-3ab+6ab-6a+2b,
=3ab-6a+2b.
点评:此题主要考查了有理数的运算,以及乘法的分配律和整式的加减运算,题目比较典型.
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