题目内容
如图,点B,C在DE上,AB=AC,CD=BE,求证:AD=AE.
证明:∵AB=AC,
∴∠ABC=∠ACB.
∴∠ABD=∠ACE.
∵CD=BE,CD=DB+BC,BE=CE+BC,
∴DB=CE.
∵AB=AC,∠ABD=∠ACE,DB=CE,
∴△ABD≌△ACE.
∴AD=AE.
∴∠ABC=∠ACB.
∴∠ABD=∠ACE.
∵CD=BE,CD=DB+BC,BE=CE+BC,
∴DB=CE.
∵AB=AC,∠ABD=∠ACE,DB=CE,
∴△ABD≌△ACE.
∴AD=AE.
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