题目内容
计算或化简:
(1)(-
)2÷
-12×(
-
)
(2)6(
x2-xy+
y2)-2(x2+
xy+
y2).
(1)(-
| 1 |
| 3 |
| 1 |
| 33 |
| 2 |
| 3 |
| 1 |
| 6 |
(2)6(
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 2 |
考点:有理数的混合运算,整式的加减
专题:
分析:(1)先算乘方,再算乘除,最后算加减;
(2)先去括号,再合并同类项即可.
(2)先去括号,再合并同类项即可.
解答:解:(1)原式=
×27-12×
+12×
=3-8+2
=-3;
(2)原式=4x2-6xy+3y2-2x2-xy-y2
=2x2-7xy+2y2.
| 1 |
| 9 |
| 2 |
| 3 |
| 1 |
| 6 |
=3-8+2
=-3;
(2)原式=4x2-6xy+3y2-2x2-xy-y2
=2x2-7xy+2y2.
点评:本题考查了有理数的混合运算以及整式的加减,注意符号的变化是解题的关键.
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