题目内容
当1≤x≤2时,经化简
+
等于______.
x+2
|
x-2
|
∵1≤x≤2,
∴
+
=
+
=
+1+1-
=2.
故答案为:2.
∴
x+2
|
x-2
|
=
(
|
(
|
=
| x-1 |
| x-1 |
=2.
故答案为:2.
练习册系列答案
相关题目
题目内容
x+2
|
x-2
|
x+2
|
x-2
|
(
|
(
|
| x-1 |
| x-1 |