题目内容
| 1 |
| x2-3x+2 |
| 1 |
| x2-5x+6 |
| 1 |
| x2-4x+3 |
分析：先通分，再把分子相加减即可．
解答：解：原式=
+
+
=
=
=
=
．
| 1 |
| (x-2)(x-1) |
| 1 |
| (x-2)(x-3) |
| 1 |
| (x-1)(x-3) |
=
| x-3+x-1+x-2 |
| (x-1)(x-2)(x-3) |
=
| x-3+x-1+x-2 |
| (x-1)(x-2)(x-3) |
=
| 3(x-2) |
| (x-1)(x-2)(x-3) |
=
| 3 |
| (x-1)(x-3) |
点评：本题考查的是分式的加减法，熟知异分母分式的加减就转化为同分母分式的加减是解答此题的关键．
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使分式
有意义的x的取值范围是（ ）
| x-1 |
| x2-3x+2 |
| A、x≠1 | B、x≠2 |
| C、x≠1且x≠2 | D、x可为任何数 |