题目内容
计算:
(1)
-
+
;
(2)
+3
-
+
;
(3)
(2
+4
-3
);
(4)
•(
÷2
).
(1)
| 27 |
| 12 |
| 45 |
(2)
| 8 |
|
| 1 | ||
|
| ||
| 2 |
(3)
| ||
| 2 |
| 12 |
|
| 48 |
(4)
| ||
| 2b |
|
|
分析:(1)把各个根式化成最简二次根式,再合并同类二次根式即可;
(2)把各个根式化成最简二次根式,再合并同类二次根式即可;
(3)根据乘法的分配律展开,再算乘法,最后合并即可;
(4)系数和被开方数分别相乘或相除,最后开方后化简即可.
(2)把各个根式化成最简二次根式,再合并同类二次根式即可;
(3)根据乘法的分配律展开,再算乘法,最后合并即可;
(4)系数和被开方数分别相乘或相除,最后开方后化简即可.
解答:解:(1)原式=3
-2
+3
=
+3
;
(2)原式=2
+3×
-
+
=2
+
-
+
=
+
;
(3)原式=
×2
+
×4
-
×3
=2
+1-6
=1-4
;
(4)原式=(
•1•
)
=
=
.
| 3 |
| 3 |
| 5 |
=
| 3 |
| 5 |
(2)原式=2
| 2 |
| ||
| 3 |
| ||||
|
| ||
| 2 |
=2
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 1 |
| 2 |
| 3 |
=
| 3 |
| 2 |
| 2 |
| 3 |
| 2 |
| 3 |
(3)原式=
| ||
| 2 |
| 12 |
| ||
| 2 |
|
| ||
| 2 |
| 48 |
=2
| 6 |
| 6 |
=1-4
| 6 |
(4)原式=(
| 1 |
| 2b |
| 1 |
| 2 |
3a•
|
=
| 1 |
| 4b |
| 3b2 |
=
| ||
| 4 |
点评:本题口岸成了二次根式的混合运算,主要考查学生的化简能力,题目比较典型,但是一道比较容易出错的题目.
练习册系列答案
相关题目