ÌâÄ¿ÄÚÈÝ

4£®¹Û²ìÏÂÁи÷Êý$\frac{1}{1}$£¬$\frac{3}{4}$£¬-$\frac{5}{7}$£¬-$\frac{7}{10}$£¬$\frac{9}{13}$£¬$\frac{11}{16}$£¬-$\frac{13}{19}$£¬-$\frac{15}{22}$£¬$\frac{17}{25}$£¬¡­¸ù¾Ý¹æÂɽâ´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÕâÁÐÊýÖеĵÚ16¸öÊý¡¢µÚ33¸öÊý·Ö±ðÊǶàÉÙ£¿
£¨2£©ÇëÓÃnµÄ´úÊýʽ±íʾµÚn¸öÊýan£®

·ÖÎö £¨1£©·Ö×ÓÊÇ´Ó1¿ªÊ¼µÄÁ¬ÐøÆæÊý£¬·ÖĸÊÇǰһ¸ö·Öĸ¼Ó3µÄºÍ£¬´ÓµÚÒ»¸ö·ÖÊý¿ªÊ¼£¬Á½ÕýÁ½¸º£¬ÒԴ˲»¶ÏÅÅÁУ¬¾Ý´Ë¿ÉÇó½â£»
£¨2£©¸ù¾Ý£¨1£©µÄÍÆÀí¹ý³Ì£¬·ÖÀàÌÖÂÛ¼´¿É£®

½â´ð ½â£º£¨1£©¡ß·Ö×ÓµÄÊý×ÖΪ£º1=1¡Á2-1£¬
3=2¡Á2-1£¬
-5=-£¨3¡Á2-1£©£¬
-7=-£¨4¡Á2-1£©£¬
·ÖĸµÄÊý×ÖΪ£º1=1¡Á3-2£¬
4=2¡Á3-2£¬
7=3¡Á3-2£¬
10=4¡Á3-2£¬
¡àµÚ16¸öÊýΪ£º$-\frac{2¡Á16-1}{3¡Á16-2}$=$-\frac{31}{46}$£¬
µÚ33¸öÊýΪ£º$\frac{2¡Á33-1}{3¡Á33-2}$=$\frac{65}{97}$£»

£¨2£©ÓÉ£¨1£©µÃ£¬µÚn¸öÊýan£¬
µ±n±»4³ýÓà1£¬2ʱ£¬an=$\frac{2n-1}{3n-2}$£¬
µ±n±»4³ýÓà3»òÕû³ýʱ£¬an=$-\frac{2n-1}{3n-2}$£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²éÁËÊý×ֵı仯¹æÂÉ£¬¸ù¾ÝÒÑÖªµÃ³ö·Ö×Ó£¬·Öĸ£¬·ûºÅµÄ±ä»¯¹æÂÉÊǽâ´ð´ËÌâµÄ¹Ø¼ü£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø