题目内容
化简:(| x+1 |
| x2-x |
| x |
| x2-2x+1 |
| 1 |
| x |
分析:先通分,再进行分式的混合运算.
解答:解:原式=[
-
]÷
=[
-
]×x
=
×x
=-
.
| x+1 |
| x(x-1) |
| x |
| (x-1)2 |
| 1 |
| x |
=[
| (x+1)(x-1) |
| x(x-1)2 |
| x2 |
| x(x-1)2 |
=
| x2-1-x2 |
| x(x-1)2 |
=-
| 1 |
| (x-1)2 |
点评:本题考查了分式的混合运算,通分是解此题的关键.
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