题目内容
已知y=
÷
-
.当x为何值时,y的值为
.
| x |
| x2-x |
| x2-1 |
| x2-2x+1 |
| 2 |
| x+1 |
| 1 |
| 3 |
根据题意得,
÷
-
=
,
×
-
=
,
-
=
,
解得x=-4,
经检验x=-4是原方程的根;
∴原方程的解为:x=-4.
| x |
| x2-x |
| x2-1 |
| x2-2x+1 |
| 2 |
| x+1 |
| 1 |
| 3 |
| x |
| x(x-1) |
| (x-1)2 |
| (x-1)(x+1) |
| 2 |
| x+1 |
| 1 |
| 3 |
-
| 1 |
| x+1 |
| 1 |
| 3 |
解得x=-4,
经检验x=-4是原方程的根;
∴原方程的解为:x=-4.
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已知方程
-
=2,若设
=a,则原方程变形并整理为( )
| x |
| x2-1 |
| x2-1 |
| x |
| x |
| x2-1 |
| A、a2-2a+1=0 |
| B、a2+a-2=0 |
| C、a2-2a-1=0 |
| D、a2+2a-1=0 |