ÌâÄ¿ÄÚÈÝ
7£®·ÖÎö ¸ù¾Ý¹´¹É¶¨Àí¿ÉÒÔÇóµÃa2+b2µÈÓÚ´óÕý·½ÐεÄÃæ»ý£¬È»ºóÇóËĸöÖ±½ÇÈý½ÇÐεÄÃæ»ý£¬¼´¿ÉµÃµ½abµÄÖµ£¬È»ºó¸ù¾Ý£¨a+b£©2=a2+2ab+b2¼´¿ÉÇó½â£®
½â´ð ½â£º¸ù¾Ý¹´¹É¶¨Àí¿ÉµÃa2+b2=13£¬
ËĸöÖ±½ÇÈý½ÇÐεÄÃæ»ýÊÇ£º$\frac{1}{2}$ab¡Á4=13-1=12£¬¼´2ab=12£¬
Ôò£¨a+b£©2=a2+2ab+b2=13+12=25£®
¹Ê´ð°¸Îª£º25£®
µãÆÀ ±¾Ì⿼²é¹´¹É¶¨Àí£¬ÒÔ¼°Íêȫƽ·½Ê½£¬ÕýÈ·¸ù¾ÝͼÐεĹØÏµÇóµÃa2+b2ºÍabµÄÖµÊǹؼü£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
17£®Èôµ¥Ïîʽ-x2a-1y4Óë2xy4ÊÇͬÀàÏÔòʽ×Ó£¨1-a£©2015=£¨¡¡¡¡£©
| A£® | 0 | B£® | 1 | C£® | -1 | D£® | 1»ò-1 |
18£®¶þ´Îº¯Êýy=-2£¨x-3£©2+1µÄͼÏóµÄ¶Ô³ÆÖáÊÇ£¨¡¡¡¡£©
| A£® | Ö±Ïßx=-2 | B£® | Ö±Ïßx=-3 | C£® | Ö±Ïßx=3 | D£® | Ö±Ïßx=1 |
15£®¹ØÓÚÕý±ÈÀýº¯Êýy=-2x£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
| A£® | yËæxµÄÔö´ó¶øÔö´ó | |
| B£® | ͼÏóÊǾ¹ýµÚÒ»¡¢µÚ¶þÏóÏÞµÄÒ»ÌõÖ±Ïß | |
| C£® | ͼÏóÏòÉÏÆ½ÒÆ1¸öµ¥Î»³¤¶ÈºóµÃµ½Ö±Ïßy=-2x+1 | |
| D£® | µã£¨1£¬2£©ÔÚÆäͼÏóÉÏ |
2£®
Èçͼ£¬¹Û²ìͼÏó£¬ÅжÏÏÂÁÐ˵·¨´íÎóµÄÊÇ£¨¡¡¡¡£©
| A£® | ·½³Ì×é$\left\{\begin{array}{l}y=2x-1\\ y=-\frac{3}{5}x+\frac{8}{5}\end{array}\right.$£®µÄ½âÊÇ $\left\{\begin{array}{l}x=1\\ y=1.\end{array}\right.$ | |
| B£® | ²»µÈʽ-$\frac{3}{5}$x+$\frac{8}{5}$¡Ü2x-1µÄ½â¼¯ÊÇx¡Ý1 | |
| C£® | ²»µÈʽ-$\frac{3}{5}$x+$\frac{8}{5}$£¾2x-1µÄ½â¼¯ÊÇx£¾1 | |
| D£® | ·½³Ì-$\frac{3}{5}$x+$\frac{8}{5}$=2x-1µÄ½âÊÇx=1 |