题目内容
先化简,再求值:| x2-1 |
| x |
| 2x-1 |
| x |
分析:此题的运算顺序:先把括号里式子通分,再把除法转化为乘法,约分化为最简,最后代值计算.
解答:解:原式=
÷(
-
)
=
÷(
)
=
×(
)
=-(x+1)=-x-1;
当x=2时,原式=-3.
| (x+1)(x-1) |
| x |
| x |
| x |
| 2x-1 |
| x |
=
| (x+1)(x-1) |
| x |
| 1-x |
| x |
=
| (x+1)(x-1) |
| x |
| x |
| 1-x |
=-(x+1)=-x-1;
当x=2时,原式=-3.
点评:本题的关键是化简,然后把给定的值代入求值.
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