题目内容
(1)(6×1010)÷
(2)
a2x2)=-5a;
(3)
(4)(3x3y2+x4y2-
xy
xy)÷
xy=
(-3×105)
(-3×105)
=-2×105;(2)
(
a-1x-2)
| 25 |
| 2 |
(
a-1x-2)
•(-| 25 |
| 2 |
| 2 |
| 5 |
(3)
(ab-bn+2cn)
(ab-bn+2cn)
÷n=a-b+2c;(4)(3x3y2+x4y2-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
6x2y
6x2y
+2x3y
2x3y
-1.分析:各式利用运算法则计算即可得到结果.
解答:解:(1)(6×1010)÷(-3×105)=-2×105;
(2)(
a-1x-2)•(-
a2x2)=-5a;
(3)(ab-bn+2cn)÷n=a-b+2c;
(4)(3x3y2+x4y2-
xy)÷
xy=6x2y+2x3y-1.
故答案为:(1)-3×105;(2)
a-1x-2;(3)ab-bn+2cn;(4)
xy;6x2y;2x3y.
(2)(
| 25 |
| 2 |
| 2 |
| 5 |
(3)(ab-bn+2cn)÷n=a-b+2c;
(4)(3x3y2+x4y2-
| 1 |
| 2 |
| 1 |
| 2 |
故答案为:(1)-3×105;(2)
| 25 |
| 2 |
| 1 |
| 2 |
点评:此题考查了整式的混合运算,熟练掌握运算法则是解本题的关键.
练习册系列答案
相关题目