题目内容
先化简,再求值:| x2-2x |
| x2-1 |
| 2x-1 |
| x+1 |
| 2 |
分析:本题的关键是正确进行分式的通分、约分,并准确代值计算.
解答:解:原式=
÷(
-
)
=
×
=-
,
当x=
+1时,原式=-
=-
=-
.
| x2-2x |
| x2-1 |
| 2x-1 |
| x+1 |
| x2-1 |
| x+1 |
=
| x2-2x |
| x2-1 |
| x+1 |
| 2x-x2 |
=-
| 1 |
| x-1 |
当x=
| 2 |
| 1 |
| x-1 |
| 1 | ||
|
| ||
| 2 |
点评:解答本题的关键是对分式进行化简,代值计算要仔细,最后结果要注意分母有理化.
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