题目内容
(1)计算:cos60°+|1-
|-(2-tan30°)+(
)-1;
(2)先化简,再求值:
÷
+
(其中a=3,b=
).
| 3 |
| 2 |
| 5 |
(2)先化简,再求值:
| a2+ab |
| b |
| a2-b2 |
| ab |
| b-a |
| a2-2ab+b2 |
| 1 |
| 2 |
(1)原式=
+(
-1)-(2-
)+
=
+
-1-2+
+
=
;
(2)原式=
÷
+
=
×
+
=
-
=
当a=3,b=
时,原式=
=
=
.
| 1 |
| 2 |
| 3 |
| ||
| 3 |
| 5 |
| 2 |
=
| 1 |
| 2 |
| 3 |
| ||
| 3 |
| 5 |
| 2 |
=
4
| ||
| 3 |
(2)原式=
| a(a+b) |
| b |
| (a-b)(a+b) |
| ab |
| b-a |
| (a-b)2 |
=
| a(a+b) |
| b |
| ab |
| (a-b)(a+b) |
| b-a |
| (a-b)2 |
=
| a2 |
| a-b |
| 1 |
| a-b |
=
| a2-1 |
| a-b |
当a=3,b=
| 1 |
| 2 |
| a2-1 |
| a-b |
| 32-1 | ||
3-
|
| 16 |
| 5 |
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