题目内容
因式分解:x3(a+1)-xy(x-y)(a+b)+y3(b+1).
考点:因式分解-分组分解法
专题:
分析:首先去括号,进而重新分组,利用提取公因式法分解因式得出即可.
解答:解:x3(a+1)-xy(x-y)(a-b)+y3(b+1)
=ax3+x3-x2y(a-b)+xy2(a-b)+by3+y3
=ax3+x3-x2ya+bx2y+axy2-bxy2+by3+y3
=a(x3-x2y+xy2)+b(y3+x2y-xy2)+x3+y3
=ax(x2-xy+y2)+by(x2-xy+y2)+(x+y)(x2-xy+y2)
=(ax+by+x+y)(x2-xy+y2).
=ax3+x3-x2y(a-b)+xy2(a-b)+by3+y3
=ax3+x3-x2ya+bx2y+axy2-bxy2+by3+y3
=a(x3-x2y+xy2)+b(y3+x2y-xy2)+x3+y3
=ax(x2-xy+y2)+by(x2-xy+y2)+(x+y)(x2-xy+y2)
=(ax+by+x+y)(x2-xy+y2).
点评:此题主要考查了分组分解法分解因式,正确分组得出是解题关键.
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