题目内容
已知3xa+1yb-2与
x2是同类项,求2a2b+3a2b-
a2b的值.
| 2 |
| 5 |
| 1 |
| 2 |
由同类项的定义得
,
解得
,
2a2b+3a2b-
a2b
=
a2b,
=
×12×2
=9.
|
解得
|
2a2b+3a2b-
| 1 |
| 2 |
=
| 9 |
| 2 |
=
| 9 |
| 2 |
=9.
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