题目内容
因式分(1)2a2-4a+2 (2)xy2-2xy+2y-4.
(1)2a2-4a+2,
=2(a2-2a+1),
=2(a-1)2;
(2)xy2-2xy+2y-4,
=xy(y-2)+2(y-2),
=(y-2)(xy+2).
=2(a2-2a+1),
=2(a-1)2;
(2)xy2-2xy+2y-4,
=xy(y-2)+2(y-2),
=(y-2)(xy+2).
练习册系列答案
相关题目
题目内容