题目内容
| 4 |
| a2-4 |
| 2 |
| a+2 |
| 1 |
| a-2 |
分析:根据异分母分式加减法法则计算:把分母不相同的几个分式化成分母相同的分式,叫做通分,经过通分,异分母分式的加减就转化为同分母分式的加减.
解答:解:原式=
+
-
=
+
-
=
=
=
.
| 4 |
| (a+2)(a-2) |
| 2 |
| a+2 |
| 1 |
| a-2 |
=
| 4 |
| (a+2)(a-2) |
| 2(a-2) |
| (a+2)(a-2) |
| a+2 |
| (a+2)(a-2) |
=
| 4+2a-4-a-2 |
| (a+2)(a-2) |
=
| a-2 |
| (a+2)(a-2) |
=
| 1 |
| a+2 |
点评:本题考查了分式的加减法法则,解题时牢记法则是关键,此题比较简单,但计算时要细心才行.
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