题目内容
(1)计算:(4a-5b)2-2(4a-5b)(3a-2b).
(2)先化简,再求值:x3-2x[
x2-3(
x-1)-
x],其中x=3.
(2)先化简,再求值:x3-2x[
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 4 |
(1)原式=16a2-40ab+25b2-2(12a2-23ab+10b2)
=16a2-40ab+25b2--24a2+46ab-20b2
=-8a2+6ab+5b2;
(2)原式=x3-2x[
x2-
x+3-
x]
=x3-x3+x2-6x+
x2
=
x2-6x,
当x=3时,
原式=
×32-6×3
=-
.
=16a2-40ab+25b2--24a2+46ab-20b2
=-8a2+6ab+5b2;
(2)原式=x3-2x[
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
=x3-x3+x2-6x+
| 1 |
| 2 |
=
| 3 |
| 2 |
当x=3时,
原式=
| 3 |
| 2 |
=-
| 9 |
| 2 |
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