题目内容
计算:
(1)
÷
;
(2)
÷
.
(1)
| ab3 |
| 2c3 |
| -5a2b2 |
| 4cd |
(2)
| x2-4y2 |
| x2+2xy+y2 |
| x+2y |
| 2x2+2xy |
(1)原式=
•
=-
;
(2)原式=
•
=
=
.
| ab3 |
| 2c2 |
| 4cd |
| -5a2b2 |
=-
| 2bd |
| 5ac2 |
(2)原式=
| (x+2y)(x-2y) |
| (x+y)2 |
| 2x(x+y) |
| x+2y |
=
| 2x(x-2y) |
| x+y |
=
| 2x2-4xy |
| x+y |
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